2m^2=-18m

Solution for 2m^2=-18m equation:

2m^2=-18m

We move all terms to the left:

2m^2-(-18m)=0

We get rid of parentheses

2m^2+18m=0

a = 2; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·2·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*2}=\frac{-36}{4}
=-9
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*2}=\frac{0}{4}
=0
$